LM2664
www.ti.com
SNVS005E –NOVEMBER 1999–REVISED DECEMBER 2014
9 Application and Implementation
NOTE
Information in the following applications sections is not part of the TI component
specification, and TI does not warrant its accuracy or completeness. TI’s customers are
responsible for determining suitability of components for their purposes. Customers should
validate and test their design implementation to confirm system functionality.
9.1 Application Information
The LM2664 CMOS charge-pump voltage converter inverts a positive voltage in the range of 1.8 V to 5.5 V to
the corresponding negative voltage of −1.8 V to −5.5 V. The LM2664 uses two low cost capacitors to provide up
to 40 mA of output current. The LM2664 operates at 160-kHz oscillator frequency to reduce output resistance
and voltage ripple. With an operating current of only 220 µA (operating efficiency greater than 91% with most
loads) and 1 µA typical shutdown current, the LM2664 provides ideal performance for battery powered systems.
9.2 Typical Application - Voltage Inverter
Figure 11. Voltage Inverter
9.2.1 Design Requirements
Example requirements for typical voltage inverter applications:
DESIGN PARAMETER EXAMPLE VALUE
Input voltage range 1.8 V to 5.5 V
Output current 0 mA to 40 mA
Boost switching frequency 80 kHz
9.2.2 Detailed Design Requirements
The main application of LM2664 is to generate a negative supply voltage. The voltage inverter circuit uses only
two external capacitors as shown in Voltage Inverter and 5 V to −10 V Converter. The range of the input supply
voltage is 1.8 V to 5.5 V.
The output characteristics of this circuit can be approximated by an ideal voltage source in series with a
resistance. The voltage source equals −(V+). The output resistance ROUT is a function of the ON resistance of the
internal MOSFET switches, the oscillator frequency, the capacitance and equivalent series resistance (ESR) of
C1and C2. Since the switching current charging and discharging C1is approximately twice as the output current,
the effect of the ESR of the pumping capacitor C1will be multiplied by four in the output resistance. The output
capacitor C2is charging and discharging at a current approximately equal to the output current, therefore, its
ESR only counts once in the output resistance. A good approximation of ROUT is:
where
• RSW is the sum of the ON resistance of the internal MOSFET switches shown in Figure 10. (1)
High capacitance, low ESR capacitors will reduce the output resistance.
Copyright © 1999–2014, Texas Instruments Incorporated Submit Documentation Feedback 9
Product Folder Links: LM2664