TSM102/A
7/9
Fi gure 2 : The Application Sc hem atic - Battery Charge r Secondary Side
The first comparator ensures the “Low Battery”
signal generation thanks to the comparison of a
part of the charger’s output voltage (resistor
bridge R17, R19) and the reference voltage. Prop-
er hysteres is is given thanks to R20. An improv e-
ment t o the chargers sec urity and to the b attery’s
life time optimization is achieved by lowering the
current control measurement thanks to Q1 that
shunts the resistor R9 when the battery’s voltage
is below the “Low Battery” level.
The second comparator ensures the “End of
Charge” signal generation thanks to the compari-
son of a part of the charger’s output voltage (resis-
tor bridge R1, R2, R3) and the reference voltage.
When either of t hese t wo signals is act i ve, the cor-
responding LED is polarized for convenient visual-
ization of the battery status.
3 - CALCULATION OF THE ELEMENTS
All the components values have been chosen for a
two-Lithiu m-Ion bat teries charge application :
■C urrent Control : 720mA (Low Battery current
con trol : 250mA)
■Voltage Control : 8.4V (= 2x 4.2V)
■Low Battery : 5.6V (= 2x 2.5V + 0.6V)
■End of Charge : 8.3V (= 2x 4.15V)
Current Control :
The voltage reference is polarized thanks to the
R4 res istor (2.5mA ), and t he ca thode of the ref er-
enc e gives a fixed 2.500V voltage.
I = U / R = [Vref( R8 + R9 ) / (R7 + R8 + R9) ] / Rs
= [2.5 x (390 + 820) / (10000 + 390 + 820)] / 0.375
= 720mA
I = 720mA
P = power dissipation t hrough the sense resistor =
R I2 = 0.375 x 0.7202 = 194mW
In case of “Low Battery” conditions, the current
con trol is lowered thanks to the following
equat ion :
I = U / R = [ Vref R8 / (R7 + R8) ] / Rs
= [ 2.5 x 390 / (10000 + 390 ) ] / 0.375
= 250m A
I (LoBa tt) = 250mA
Voltage Control :
Vout = Vref / [ R2 / (R1 + R2 + R3) ]
= 2.5 / [ 56 / (131.5 + 56 + 0.68 ) ]
= 8.400V
Vout = 8.400V
Low Battery signal :
If R5 = 0Ω and R6 = open :
Vout(LoBatt) = Vref / [ R19 / ( R17 + R19 ) ]
= 2.5 / [ 10 / (12.4 + 10) ]
= 5.6V
Vout(L oBat t ) = 5.6V
En d of Charge signal :
Vout(EOC ) = Vref / [ (R2 + R3 ) / (R1 + R2 + R3 ) ]
= 2.5 / [(56 + 0.68) / (131.5 + 56 + 0.68)]
= 8.300V
Vout (EOC)= 8.300V