INTRODUCTION
The function of a heatsink is to increase the surface
area available for the transfer of heat from a
component or device thereby increasing the amount of
heat that can be dissipated.
The following products/services are available:
1 A range of Standard heatsinks and accessories
which permit optimum flexibility in the design of
Electrical and Electronic equipment requiring
heatsink applications.
2 Custom designed heatsinks. We have facilities
available which enable us to provide design and
manufacturing of custom and specialised heatsinks
to your requirements.
The main factors to consider when selecting a
heatsink are:-
1 Geometry
2 Thermal Resistance
3 Cost
Defining the necessary heatsink performance.
In order to calculate the maximum acceptable thermal
resistance for the heatsink so that the device being
cooled does not overheat it is first necessary to define
the thermal parameters under which it is to operate.
The basic equation for thermal equilibrium is:-
Temperature difference
across the system
Power dissipated =
Sum of all the thermal
resistance in the heat
flow path.
Thus PD = Tj - Ta
Øjc + Øcs + Øsa
Where PD = Power dissipation (W)
Tj = Max allowable junction temp (ºC)
(specified by device manufacturer)
Ta = Ambient temperature (ºC)
Øjc = Thermal resistance junction to
case (ºC/W)
(specified by device manufacturer)
Øcs = Thermal resistance, case to
heatsink (ºC/W)
Øsa = Thermal resistance, heatsinks to
ambient air (ºC/W)
The maximum value for thermal resistance heatsink to
air (sa) is usually determined by rearranging
equation 1 to the following:
Øsa = Tj - Ta - (Øjc + Øcs)
PD
The result of the above equation provides a thermal
resistance value which must be equalled or bettered
by the heatsink selected.
A semi-conductor device is to be operated with its
junction temperature not exceeding 80ºC whilst dissi-
pating 16 watts to ambient air at a temperature of40ºC.
The thermal resistance, junction to case, is specified
by the manufacturer as 1.25ºC/W and the thermal
resistance, case to sink (using an insulating washer and
thermally conductive compound) is taken as 0.50ºC/W.
Øsa = 80 - 40 - (1.25 + 0.50)
16
= 0.75ºC/W
The heatsink therefore must have a thermal resistance
which does not exceed 0.75ºC/W.
HEATSINK SELECTION
EQUATION 1
EQUATION 2
EXAMPLE
Thermal Performance of any heatsink is influenced by
many factors and for this reason all performance fig-
ures quoted should be treated as indicative only. It is
recommended that the effectiveness of any heatsink is
tested in the specific operating environment in which
it will be subjected.
2